Roorkee, 14 June 2019: Indian Institute of Technology (IIT) Roorkee, the organizing institute of JEE (Advanced) 2019, has announced JEE (Advanced) 2019 results.

A total number of 161,319 candidates appeared in both papers 1 and 2 in JEE (Advanced) 2019. A total of 38705 candidates have qualified JEE (Advanced) 2019. Of the total qualified candidates, 5356 are females.

Mr. Gupta Kartikey Chandresh of Ballarpur is the top ranker in Common Rank List (CRL) in JEE (Advanced) 2019. He obtained 346 marks out of 372 marks. Ms. Shabnam Sahay of Madhapur is the top ranked female with CRL 10. She obtained 308 marks out of 372 marks.

Following are more details about the qualified candidates:

1. Total number of qualified boys: 33,349
2. Total number of qualified girls: 5,356
3. Total number of qualified general (GE) candidates: 15,566
4. Total number of qualified general (GEN-EWS) candidates: 3,636
5. Total number of qualified OBC-NCL candidates: 7,651
6. Total number of qualified SC candidates: 8,758
7. Total number of qualified ST candidates: 3,094

Following are the zonal top rankers:

IIT Bombay – GUPTA KARTIKEY CHANDRESH (CRL 1)

IIT Delhi – HIMANSHU GAURAV SINGH (CRL 2)

IIT Guwahati –  PRADIPTA PARAG BORA (CRL 28)

IIT Kanpur – DHRUV ARORA (CRL 24)

IIT Kharagpur -GUDIPATY ANIKET (CRL 29)

IIT Hyderabad – GILLELLA AKASH REDDY (CRL 4)

IIT Roorkee – JAYESH SINGLA (CRL 17)